Integrand size = 19, antiderivative size = 77 \[ \int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx=x \operatorname {AppellF1}\left (\frac {1}{4},2,-p,\frac {5}{4},x^4,-b x^4\right )+\frac {2}{3} x^3 \operatorname {AppellF1}\left (\frac {3}{4},2,-p,\frac {7}{4},x^4,-b x^4\right )+\frac {1}{5} x^5 \operatorname {AppellF1}\left (\frac {5}{4},2,-p,\frac {9}{4},x^4,-b x^4\right ) \]
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Time = 0.05 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {1254, 440, 524} \[ \int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx=x \operatorname {AppellF1}\left (\frac {1}{4},2,-p,\frac {5}{4},x^4,-b x^4\right )+\frac {1}{5} x^5 \operatorname {AppellF1}\left (\frac {5}{4},2,-p,\frac {9}{4},x^4,-b x^4\right )+\frac {2}{3} x^3 \operatorname {AppellF1}\left (\frac {3}{4},2,-p,\frac {7}{4},x^4,-b x^4\right ) \]
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Rule 440
Rule 524
Rule 1254
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\left (1+b x^4\right )^p}{\left (-1+x^4\right )^2}+\frac {2 x^2 \left (1+b x^4\right )^p}{\left (-1+x^4\right )^2}+\frac {x^4 \left (1+b x^4\right )^p}{\left (-1+x^4\right )^2}\right ) \, dx \\ & = 2 \int \frac {x^2 \left (1+b x^4\right )^p}{\left (-1+x^4\right )^2} \, dx+\int \frac {\left (1+b x^4\right )^p}{\left (-1+x^4\right )^2} \, dx+\int \frac {x^4 \left (1+b x^4\right )^p}{\left (-1+x^4\right )^2} \, dx \\ & = x F_1\left (\frac {1}{4};2,-p;\frac {5}{4};x^4,-b x^4\right )+\frac {2}{3} x^3 F_1\left (\frac {3}{4};2,-p;\frac {7}{4};x^4,-b x^4\right )+\frac {1}{5} x^5 F_1\left (\frac {5}{4};2,-p;\frac {9}{4};x^4,-b x^4\right ) \\ \end{align*}
\[ \int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx=\int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx \]
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\[\int \frac {\left (b \,x^{4}+1\right )^{p}}{\left (-x^{2}+1\right )^{2}}d x\]
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\[ \int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx=\int { \frac {{\left (b x^{4} + 1\right )}^{p}}{{\left (x^{2} - 1\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx=\int { \frac {{\left (b x^{4} + 1\right )}^{p}}{{\left (x^{2} - 1\right )}^{2}} \,d x } \]
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\[ \int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx=\int { \frac {{\left (b x^{4} + 1\right )}^{p}}{{\left (x^{2} - 1\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {\left (1+b x^4\right )^p}{\left (1-x^2\right )^2} \, dx=\int \frac {{\left (b\,x^4+1\right )}^p}{{\left (x^2-1\right )}^2} \,d x \]
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